-3(8u-6)+8u=2(u+2)

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Solution for -3(8u-6)+8u=2(u+2) equation: 



-3(8u-6)+8u=2(u+2)

We move all terms to the left:

-3(8u-6)+8u-(2(u+2))=0

We add all the numbers together, and all the variables

8u-3(8u-6)-(2(u+2))=0

We multiply parentheses

8u-24u-(2(u+2))+18=0



We calculate terms in parentheses: -(2(u+2)), so:

2(u+2)

We multiply parentheses

2u+4

Back to the equation:

-(2u+4)



We add all the numbers together, and all the variables

-16u-(2u+4)+18=0

We get rid of parentheses

-16u-2u-4+18=0

We add all the numbers together, and all the variables

-18u+14=0

We move all terms containing u to the left, all other terms to the right

-18u=-14

u=-14/-18

u=7/9

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