1/2(x-7)-4=2/5(x-3)

Solution for 1/2(x-7)-4=2/5(x-3) equation:

1/2(x-7)-4=2/5(x-3)

We move all terms to the left:

1/2(x-7)-4-(2/5(x-3))=0


Domain of the equation: 2(x-7)!=0

x∈R



Domain of the equation: 5(x-3))!=0

x∈R


We calculate fractions


(5xx/(2(x-7)*5(x-3)))+(-4xx/(2(x-7)*5(x-3)))-4=0


We calculate terms in parentheses: +(5xx/(2(x-7)*5(x-3))), so:

5xx/(2(x-7)*5(x-3))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)



We calculate terms in parentheses: +(-4xx/(2(x-7)*5(x-3))), so:

-4xx/(2(x-7)*5(x-3))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)


We get rid of parentheses

5xx-4xx-4=0

We move all terms containing x to the left, all other terms to the right

5xx-4xx=4