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2(x-1)/3=3(x-2)/4=1
We move all terms to the left:
2(x-1)/3-(3(x-2)/4)=0
We calculate fractions
2x/()+(-(3(x-2)*3)/()=0
We calculate terms in parentheses: +(-(3(x-2)*3)/(), so:We get rid of parentheses
-(3(x-2)*3)/(
We multiply all the terms by the denominator
-(3(x-2)*3)
We calculate terms in parentheses: -(3(x-2)*3), so:We get rid of parentheses
3(x-2)*3
We multiply parentheses
9x-18
Back to the equation:
-(9x-18)
-9x+18
Back to the equation:
+(-9x+18)
2x/()-9x+18=0
We multiply all the terms by the denominator
2x-9x*()+18*()=0
We add all the numbers together, and all the variables
2x-9x*()=0
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