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6(x-6)=2(3x-5)-26
We move all terms to the left:
6(x-6)-(2(3x-5)-26)=0
We multiply parentheses
6x-(2(3x-5)-26)-36=0
We calculate terms in parentheses: -(2(3x-5)-26), so:We get rid of parentheses
2(3x-5)-26
We multiply parentheses
6x-10-26
We add all the numbers together, and all the variables
6x-36
Back to the equation:
-(6x-36)
6x-6x+36-36=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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