1/2(x-4)=1/3(x+3)

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Solution for 1/2(x-4)=1/3(x+3) equation: 



1/2(x-4)=1/3(x+3)

We move all terms to the left:

1/2(x-4)-(1/3(x+3))=0



Domain of the equation: 2(x-4)!=0

x∈R





Domain of the equation: 3(x+3))!=0

x∈R



We calculate fractions


(3xx/(2(x-4)*3(x+3)))+(-2xx/(2(x-4)*3(x+3)))=0



We calculate terms in parentheses: +(3xx/(2(x-4)*3(x+3))), so:

3xx/(2(x-4)*3(x+3))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-2xx/(2(x-4)*3(x+3))), so:

-2xx/(2(x-4)*3(x+3))

We multiply all the terms by the denominator


-2xx

Back to the equation:

+(-2xx)



We get rid of parentheses

3xx-2xx=0

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