4((3-3y)/8)+5y=-23

Solution for 4((3-3y)/8)+5y=-23 equation:

4((3-3y)/8)+5y=-23

We move all terms to the left:

4((3-3y)/8)+5y-(-23)=0

We add all the numbers together, and all the variables

4((-3y+3)/8)+5y-(-23)=0

We add all the numbers together, and all the variables

5y+4((-3y+3)/8)+23=0

We multiply all the terms by the denominator


5y*8)+4((-3y+3)+23*8)=0

We add all the numbers together, and all the variables

5y*8)+4((-3y+3)=0

Wy multiply elements

40y^2=0

a = 40; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·40·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{80}=0$