3(m-9)+6=6(2m-2)+42

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Solution for 3(m-9)+6=6(2m-2)+42 equation: 



3(m-9)+6=6(2m-2)+42

We move all terms to the left:

3(m-9)+6-(6(2m-2)+42)=0

We multiply parentheses

3m-(6(2m-2)+42)-27+6=0



We calculate terms in parentheses: -(6(2m-2)+42), so:

6(2m-2)+42

We multiply parentheses

12m-12+42

We add all the numbers together, and all the variables

12m+30

Back to the equation:

-(12m+30)



We add all the numbers together, and all the variables

3m-(12m+30)-21=0

We get rid of parentheses

3m-12m-30-21=0

We add all the numbers together, and all the variables

-9m-51=0

We move all terms containing m to the left, all other terms to the right

-9m=51

m=51/-9

m=-5+2/3

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