8-(7/10)h=6-(1/5)h

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Solution for 8-(7/10)h=6-(1/5)h equation:



8-(7/10)h=6-(1/5)h
We move all terms to the left:
8-(7/10)h-(6-(1/5)h)=0
Domain of the equation: 10)h!=0
h!=0/1
h!=0
h∈R
Domain of the equation: 5)h)!=0
h!=0/1
h!=0
h∈R
We add all the numbers together, and all the variables
-(+7/10)h-(6-(+1/5)h)+8=0
We multiply parentheses
-7h^2-(6-(+1/5)h)+8=0
We multiply all the terms by the denominator
-7h^2*5)h)-(6-(+8*5)h)+1=0
We add all the numbers together, and all the variables
-7h^2*5)h)-(6-40h)+1=0
Wy multiply elements
-35h^3=0
We do not support ehpression: h^3

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