1/2(x-)=1/3(x+3)

Solution for 1/2(x-)=1/3(x+3) equation:

1/2(x-)=1/3(x+3)

We move all terms to the left:

1/2(x-)-(1/3(x+3))=0


Domain of the equation: 2(x-)!=0

x∈R



Domain of the equation: 3(x+3))!=0

x∈R


We add all the numbers together, and all the variables

1/2(+x)-(1/3(x+3))=0

We calculate fractions


(3xx/(2(+x)*3(x+3)))+(-2x0/(2(+x)*3(x+3)))=0


We calculate terms in parentheses: +(3xx/(2(+x)*3(x+3))), so:

3xx/(2(+x)*3(x+3))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-2x0/(2(+x)*3(x+3))), so:

-2x0/(2(+x)*3(x+3))

We multiply all the terms by the denominator


-2x0

We add all the numbers together, and all the variables

-2x

Back to the equation:

+(-2x)


We get rid of parentheses

3xx-2x=0

We add all the numbers together, and all the variables

-2x+3xx=0