1/2(x+3)=3/8(2x-5)

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Solution for 1/2(x+3)=3/8(2x-5) equation:



1/2(x+3)=3/8(2x-5)
We move all terms to the left:
1/2(x+3)-(3/8(2x-5))=0
Domain of the equation: 2(x+3)!=0
x∈R
Domain of the equation: 8(2x-5))!=0
x∈R
We calculate fractions
(8x2/(2(x+3)*8(2x-5)))+(-6xx/(2(x+3)*8(2x-5)))=0
We calculate terms in parentheses: +(8x2/(2(x+3)*8(2x-5))), so:
8x2/(2(x+3)*8(2x-5))
We multiply all the terms by the denominator
8x2
We add all the numbers together, and all the variables
8x^2
Back to the equation:
+(8x^2)
We calculate terms in parentheses: +(-6xx/(2(x+3)*8(2x-5))), so:
-6xx/(2(x+3)*8(2x-5))
We multiply all the terms by the denominator
-6xx
Back to the equation:
+(-6xx)
We get rid of parentheses
8x^2-6xx=0

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