4c-12=4(c-3)

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Solution for 4c-12=4(c-3) equation: 



4c-12=4(c-3)

We move all terms to the left:

4c-12-(4(c-3))=0



We calculate terms in parentheses: -(4(c-3)), so:

4(c-3)

We multiply parentheses

4c-12

Back to the equation:

-(4c-12)



We get rid of parentheses

4c-4c+12-12=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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