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6x+4=4(3/4x+1)
We move all terms to the left:
6x+4-(4(3/4x+1))=0
Domain of the equation: 4x+1))!=0We multiply all the terms by the denominator
x∈R
6x*4x+4*4x+1))-(4(3+1))=0
We add all the numbers together, and all the variables
6x*4x+4*4x+1))-(44)=0
We add all the numbers together, and all the variables
6x*4x+4*4x=0
Wy multiply elements
24x^2+16x=0
a = 24; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·24·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*24}=\frac{-32}{48} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*24}=\frac{0}{48} =0 $
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