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1/2(x+3)+4x=1/5x+4
We move all terms to the left:
1/2(x+3)+4x-(1/5x+4)=0
Domain of the equation: 2(x+3)!=0
x∈R
Domain of the equation: 5x+4)!=0We add all the numbers together, and all the variables
x∈R
4x+1/2(x+3)-(1/5x+4)=0
We get rid of parentheses
4x+1/2(x+3)-1/5x-4=0
We calculate fractions
4x+5x/(10x^2+30x)+(-2xx/(10x^2+30x)-4=0
We calculate fractions
We do not support expression: x^3
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