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1/2(8x-12)=2/3(9x-6)
We move all terms to the left:
1/2(8x-12)-(2/3(9x-6))=0
Domain of the equation: 2(8x-12)!=0
x∈R
Domain of the equation: 3(9x-6))!=0We calculate fractions
x∈R
(3x9/(2(8x-12)*3(9x-6)))+(-4x8/(2(8x-12)*3(9x-6)))=0
We calculate terms in parentheses: +(3x9/(2(8x-12)*3(9x-6))), so:
3x9/(2(8x-12)*3(9x-6))
We multiply all the terms by the denominator
3x9
We add all the numbers together, and all the variables
3x^9
We do not support expression: x^9
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