6(x-2)+3=21-4(x-5)

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Solution for 6(x-2)+3=21-4(x-5) equation: 



6(x-2)+3=21-4(x-5)

We move all terms to the left:

6(x-2)+3-(21-4(x-5))=0

We multiply parentheses

6x-(21-4(x-5))-12+3=0



We calculate terms in parentheses: -(21-4(x-5)), so:

21-4(x-5)

determiningTheFunctionDomain
-4(x-5)+21

We multiply parentheses

-4x+20+21

We add all the numbers together, and all the variables

-4x+41

Back to the equation:

-(-4x+41)



We add all the numbers together, and all the variables

6x-(-4x+41)-9=0

We get rid of parentheses

6x+4x-41-9=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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