.2(4x+2)=4x-12(x+1)

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Solution for .2(4x+2)=4x-12(x+1) equation: 



.2(4x+2)=4x-12(x+1)

We move all terms to the left:

.2(4x+2)-(4x-12(x+1))=0

We multiply parentheses

0.8x-(4x-12(x+1))+0.4=0



We calculate terms in parentheses: -(4x-12(x+1)), so:

4x-12(x+1)

We multiply parentheses

4x-12x-12

We add all the numbers together, and all the variables

-8x-12

Back to the equation:

-(-8x-12)



We get rid of parentheses

0.8x+8x+12+0.4=0

We add all the numbers together, and all the variables

8.8x+12.4=0

We move all terms containing x to the left, all other terms to the right

8.8x=-12.4

x=-12.4/8.8

x=-1+2.25/5.5

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