1/2(4x-8)+6x=4+3(x-12)

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Solution for 1/2(4x-8)+6x=4+3(x-12) equation: 



1/2(4x-8)+6x=4+3(x-12)

We move all terms to the left:

1/2(4x-8)+6x-(4+3(x-12))=0



Domain of the equation: 2(4x-8)!=0

x∈R



We add all the numbers together, and all the variables

6x+1/2(4x-8)-(4+3(x-12))=0

We multiply all the terms by the denominator


6x*2(4x-8)-((4+3(x-12)))*2(4x-8)+1=0



We calculate terms in parentheses: -((4+3(x-12)))*2(4x-8), so:

(4+3(x-12)))*2(4x-8



Wy multiply elements

12x^2(4-((4+3(x-12)))*2(4x-8)+1=0

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