2x+3(4x-5)=41

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Solution for 2x+3(4x-5)=41 equation: 



2x+3(4x-5)=41

We move all terms to the left:

2x+3(4x-5)-(41)=0

We multiply parentheses

2x+12x-15-41=0

We add all the numbers together, and all the variables

14x-56=0

We move all terms containing x to the left, all other terms to the right

14x=56

x=56/14

x=4

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