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(3x+10)=(x+62)
We move all terms to the left:
(3x+10)-((x+62))=0
We get rid of parentheses
3x-((x+62))+10=0
We calculate terms in parentheses: -((x+62)), so:We get rid of parentheses
(x+62)
We get rid of parentheses
x+62
Back to the equation:
-(x+62)
3x-x-62+10=0
We add all the numbers together, and all the variables
2x-52=0
We move all terms containing x to the left, all other terms to the right
2x=52
x=52/2
x=26
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