1/2(3a-5)+1/2(a+3)=7

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Solution for 1/2(3a-5)+1/2(a+3)=7 equation: 



1/2(3a-5)+1/2(a+3)=7

We move all terms to the left:

1/2(3a-5)+1/2(a+3)-(7)=0



Domain of the equation: 2(3a-5)!=0

a∈R





Domain of the equation: 2(a+3)!=0

a∈R



We calculate fractions


(2aa/(2(3a-5)*2(a+3))+(2a3/(2(3a-5)*2(a+3))-7=0

We can not solve this equation

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