4x-3(2x-4)=3+6(x+1)-10

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Solution for 4x-3(2x-4)=3+6(x+1)-10 equation:



4x-3(2x-4)=3+6(x+1)-10
We move all terms to the left:
4x-3(2x-4)-(3+6(x+1)-10)=0
We multiply parentheses
4x-6x-(3+6(x+1)-10)+12=0
We calculate terms in parentheses: -(3+6(x+1)-10), so:
3+6(x+1)-10
determiningTheFunctionDomain 6(x+1)+3-10
We add all the numbers together, and all the variables
6(x+1)-7
We multiply parentheses
6x+6-7
We add all the numbers together, and all the variables
6x-1
Back to the equation:
-(6x-1)
We add all the numbers together, and all the variables
-2x-(6x-1)+12=0
We get rid of parentheses
-2x-6x+1+12=0
We add all the numbers together, and all the variables
-8x+13=0
We move all terms containing x to the left, all other terms to the right
-8x=-13
x=-13/-8
x=1+5/8

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