3(.5x-4)=3/2x-12

Solution for 3(.5x-4)=3/2x-12 equation:

3(.5x-4)=3/2x-12

We move all terms to the left:

3(.5x-4)-(3/2x-12)=0


Domain of the equation: 2x-12)!=0

x∈R


We multiply parentheses

3x-(3/2x-12)-12=0

We get rid of parentheses

3x-3/2x+12-12=0

We multiply all the terms by the denominator


3x*2x+12*2x-12*2x-3=0

Wy multiply elements

6x^2+24x-24x-3=0

We add all the numbers together, and all the variables

6x^2-3=0

a = 6; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·6·(-3)
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{2}}{2*6}=\frac{0-6\sqrt{2}}{12}
=-\frac{6\sqrt{2}}{12}
=-\frac{\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{2}}{2*6}=\frac{0+6\sqrt{2}}{12}
=\frac{6\sqrt{2}}{12}
=\frac{\sqrt{2}}{2}
$