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1/2(3-5x)=6-(2x+4)
We move all terms to the left:
1/2(3-5x)-(6-(2x+4))=0
Domain of the equation: 2(3-5x)!=0We add all the numbers together, and all the variables
x∈R
1/2(-5x+3)-(6-(2x+4))=0
We multiply all the terms by the denominator
-((6-(2x+4)))*2(-5x+3)+1=0
We calculate terms in parentheses: -((6-(2x+4)))*2(-5x+3), so:We add all the numbers together, and all the variables
(6-(2x+4)))*2(-5x+3
We add all the numbers together, and all the variables
-5x+(6-(2x+4)))*2(+3
Back to the equation:
-(-5x+(6-(2x+4)))*2(+3)
-(-5x+(6-(2x+4)))*23+1=0
We move all terms containing x to the left, all other terms to the right
-(-5x+(6-(2x+4)))*23=-1
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