2/5s-2+3(s-11)=50=

Solution for 2/5s-2+3(s-11)=50= equation:

2/5s-2+3(s-11)=50=

We move all terms to the left:

2/5s-2+3(s-11)-(50)=0


Domain of the equation: 5s!=0

s!=0/5

s!=0

s∈R


We add all the numbers together, and all the variables

2/5s+3(s-11)-52=0

We multiply parentheses

2/5s+3s-33-52=0

We multiply all the terms by the denominator


3s*5s-33*5s-52*5s+2=0

Wy multiply elements

15s^2-165s-260s+2=0

We add all the numbers together, and all the variables

15s^2-425s+2=0

a = 15; b = -425; c = +2;
Δ = b2-4ac
Δ = -4252-4·15·2
Δ = 180505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-\sqrt{180505}}{2*15}=\frac{425-\sqrt{180505}}{30}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+\sqrt{180505}}{2*15}=\frac{425+\sqrt{180505}}{30}
$