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1/2(2x+)=3x+13
We move all terms to the left:
1/2(2x+)-(3x+13)=0
Domain of the equation: 2(2x+)!=0We add all the numbers together, and all the variables
x∈R
1/2(+2x)-(3x+13)=0
We get rid of parentheses
1/2(+2x)-3x-13=0
We multiply all the terms by the denominator
-3x*2(+2x)-13*2(+2x)+1=0
Wy multiply elements
-6x^2(+-26x(++1=0
We use the square of the difference formula
-6x^2(-26x(+1=0
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