12-3(w+1)=9w-3(9+w)

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Solution for 12-3(w+1)=9w-3(9+w) equation:



12-3(w+1)=9w-3(9+w)
We move all terms to the left:
12-3(w+1)-(9w-3(9+w))=0
We add all the numbers together, and all the variables
-3(w+1)-(9w-3(w+9))+12=0
We multiply parentheses
-3w-(9w-3(w+9))-3+12=0
We calculate terms in parentheses: -(9w-3(w+9)), so:
9w-3(w+9)
We multiply parentheses
9w-3w-27
We add all the numbers together, and all the variables
6w-27
Back to the equation:
-(6w-27)
We add all the numbers together, and all the variables
-3w-(6w-27)+9=0
We get rid of parentheses
-3w-6w+27+9=0
We add all the numbers together, and all the variables
-9w+36=0
We move all terms containing w to the left, all other terms to the right
-9w=-36
w=-36/-9
w=+4

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