(1/x-2)+(1/x+3)=7/6

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Solution for (1/x-2)+(1/x+3)=7/6 equation: 



(1/x-2)+(1/x+3)=7/6

We move all terms to the left:

(1/x-2)+(1/x+3)-(7/6)=0



Domain of the equation: x-2)!=0

x∈R





Domain of the equation: x+3)!=0

x∈R



We add all the numbers together, and all the variables

(1/x-2)+(1/x+3)-(+7/6)=0

We get rid of parentheses

1/x+1/x-2+3-7/6=0

We calculate fractions

There is no solution for this equation

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