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1/2(18x+8)-19=1/3(9x-9)
We move all terms to the left:
1/2(18x+8)-19-(1/3(9x-9))=0
Domain of the equation: 2(18x+8)!=0
x∈R
Domain of the equation: 3(9x-9))!=0We calculate fractions
x∈R
(3x9/(2(18x+8)*3(9x-9)))+(-2x1/(2(18x+8)*3(9x-9)))-19=0
We calculate terms in parentheses: +(3x9/(2(18x+8)*3(9x-9))), so:
3x9/(2(18x+8)*3(9x-9))
We multiply all the terms by the denominator
3x9
We add all the numbers together, and all the variables
3x^9
We do not support expression: x^9
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