-2(3y-1)+2y=9+5(2y-1)

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Solution for -2(3y-1)+2y=9+5(2y-1) equation: 



-2(3y-1)+2y=9+5(2y-1)

We move all terms to the left:

-2(3y-1)+2y-(9+5(2y-1))=0

We add all the numbers together, and all the variables

2y-2(3y-1)-(9+5(2y-1))=0

We multiply parentheses

2y-6y-(9+5(2y-1))+2=0



We calculate terms in parentheses: -(9+5(2y-1)), so:

9+5(2y-1)

determiningTheFunctionDomain
5(2y-1)+9

We multiply parentheses

10y-5+9

We add all the numbers together, and all the variables

10y+4

Back to the equation:

-(10y+4)



We add all the numbers together, and all the variables

-4y-(10y+4)+2=0

We get rid of parentheses

-4y-10y-4+2=0

We add all the numbers together, and all the variables

-14y-2=0

We move all terms containing y to the left, all other terms to the right

-14y=2

y=2/-14

y=-1/7

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