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12+1/5(10c+5)=59
We move all terms to the left:
12+1/5(10c+5)-(59)=0
Domain of the equation: 5(10c+5)!=0We add all the numbers together, and all the variables
c∈R
1/5(10c+5)-47=0
We multiply all the terms by the denominator
-47*5(10c+5)+1=0
Wy multiply elements
-235c(1+1=0
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