1/2(10-8y)=-3

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Solution for 1/2(10-8y)=-3 equation: 



1/2(10-8y)=-3

We move all terms to the left:

1/2(10-8y)-(-3)=0



Domain of the equation: 2(10-8y)!=0

y∈R



We add all the numbers together, and all the variables

1/2(-8y+10)-(-3)=0

We add all the numbers together, and all the variables

1/2(-8y+10)+3=0

We multiply all the terms by the denominator


3*2(-8y+10)+1=0

Wy multiply elements

6y(-+1=0

We use the square of the difference formula

6y(-1=0

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