3+2(n+2)=2(n-8)

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Solution for 3+2(n+2)=2(n-8) equation:



3+2(n+2)=2(n-8)
We move all terms to the left:
3+2(n+2)-(2(n-8))=0
We multiply parentheses
2n-(2(n-8))+4+3=0
We calculate terms in parentheses: -(2(n-8)), so:
2(n-8)
We multiply parentheses
2n-16
Back to the equation:
-(2n-16)
We add all the numbers together, and all the variables
2n-(2n-16)+7=0
We get rid of parentheses
2n-2n+16+7=0
We add all the numbers together, and all the variables
23!=0
There is no solution for this equation

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