1/(5+y)+1/y=1

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Solution for 1/(5+y)+1/y=1 equation: 



1/(5+y)+1/y=1

We move all terms to the left:

1/(5+y)+1/y-(1)=0



Domain of the equation: (5+y)!=0

We move all terms containing y to the left, all other terms to the right

y!=-5

y∈R





Domain of the equation: y!=0

y∈R



We add all the numbers together, and all the variables

1/(y+5)+1/y-1=0

We calculate fractions


y/(y^2+5y)+(1*(y+5))/(y^2+5y)-1=0



We calculate terms in parentheses: +(1*(y+5))/(y^2+5y), so:

1*(y+5))/(y^2+5y

We add all the numbers together, and all the variables

5y+1*(y+5))/(y^2

We multiply all the terms by the denominator


5y*(y^2+1*(y+5))

Back to the equation:

+(5y*(y^2+1*(y+5)))



We multiply all the terms by the denominator


y+((5y*(y^2+1*(y+5))))*(y^2+5y)-1*(y^2+5y)=0



We calculate terms in parentheses: +((5y*(y^2+1*(y+5))))*(y^2+5y), so:

(5y*(y^2+1*(y+5))))*(y^2+5y

We add all the numbers together, and all the variables

5y+(5y*(y^2+1*(y+5))))*(y^2

Back to the equation:

+(5y+(5y*(y^2+1*(y+5))))*(y^2)

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