y(1-y)=-3(y-2)

Solution for y(1-y)=-3(y-2) equation:

y(1-y)=-3(y-2)

We move all terms to the left:

y(1-y)-(-3(y-2))=0

We add all the numbers together, and all the variables

y(-1y+1)-(-3(y-2))=0

We multiply parentheses

-1y^2+y-(-3(y-2))=0


We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)


We get rid of parentheses

-1y^2+y+3y-6=0

We add all the numbers together, and all the variables

-1y^2+4y-6=0

a = -1; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-1)·(-6)
Δ = -8
Delta is less than zero, so there is no solution for the equation