1/(2x+10)+3/2=x/(x+5)

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Solution for 1/(2x+10)+3/2=x/(x+5) equation: 



1/(2x+10)+3/2=x/(x+5)

We move all terms to the left:

1/(2x+10)+3/2-(x/(x+5))=0



Domain of the equation: (2x+10)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-10

x!=-10/2

x!=-5

x∈R





Domain of the equation: (x+5))!=0

x∈R



We calculate fractions


2x/((2x+10)*(x+5))*2)+(-(x*(2x+10)*2)/((2x+10)*(x+5))*2)+(3*(2x+10)*(x+5)))/((2x+10)*(x+5))*2)=0

We can not solve this equation

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