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9/5(x-3)=3/4(3-x)
We move all terms to the left:
9/5(x-3)-(3/4(3-x))=0
Domain of the equation: 5(x-3)!=0
x∈R
Domain of the equation: 4(3-x))!=0We add all the numbers together, and all the variables
x∈R
9/5(x-3)-(3/4(-1x+3))=0
We calculate fractions
(36x(-)/(5(x-3)*4(-1x+3)))+(-15xx/(5(x-3)*4(-1x+3)))=0
We calculate terms in parentheses: +(36x(-)/(5(x-3)*4(-1x+3))), so:
36x(-)/(5(x-3)*4(-1x+3))
We add all the numbers together, and all the variables
36x0/(5(x-3)*4(-1x+3))
We multiply all the terms by the denominator
36x0
We add all the numbers together, and all the variables
36x
Back to the equation:
+(36x)
We calculate terms in parentheses: +(-15xx/(5(x-3)*4(-1x+3))), so:We get rid of parentheses
-15xx/(5(x-3)*4(-1x+3))
We multiply all the terms by the denominator
-15xx
Back to the equation:
+(-15xx)
36x-15xx=0
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