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1.12x(1-x)=x
We move all terms to the left:
1.12x(1-x)-(x)=0
We add all the numbers together, and all the variables
1.12x(-1x+1)-x=0
We add all the numbers together, and all the variables
-1x+1.12x(-1x+1)=0
We multiply parentheses
-1x^2-1x+x=0
We add all the numbers together, and all the variables
-1x^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-2}=0$
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