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81-(4x-6)=4(x+3)+x
We move all terms to the left:
81-(4x-6)-(4(x+3)+x)=0
We get rid of parentheses
-4x-(4(x+3)+x)+6+81=0
We calculate terms in parentheses: -(4(x+3)+x), so:We add all the numbers together, and all the variables
4(x+3)+x
We add all the numbers together, and all the variables
x+4(x+3)
We multiply parentheses
x+4x+12
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
-4x-(5x+12)+87=0
We get rid of parentheses
-4x-5x-12+87=0
We add all the numbers together, and all the variables
-9x+75=0
We move all terms containing x to the left, all other terms to the right
-9x=-75
x=-75/-9
x=8+1/3
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