1-3(2x-4)=4(5-x)-8

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Solution for 1-3(2x-4)=4(5-x)-8 equation: 



1-3(2x-4)=4(5-x)-8

We move all terms to the left:

1-3(2x-4)-(4(5-x)-8)=0

We add all the numbers together, and all the variables

-3(2x-4)-(4(-1x+5)-8)+1=0

We multiply parentheses

-6x-(4(-1x+5)-8)+12+1=0



We calculate terms in parentheses: -(4(-1x+5)-8), so:

4(-1x+5)-8

We multiply parentheses

-4x+20-8

We add all the numbers together, and all the variables

-4x+12

Back to the equation:

-(-4x+12)



We add all the numbers together, and all the variables

-6x-(-4x+12)+13=0

We get rid of parentheses

-6x+4x-12+13=0

We add all the numbers together, and all the variables

-2x+1=0

We move all terms containing x to the left, all other terms to the right

-2x=-1

x=-1/-2

x=1/2

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