20(4c-3)+50c=590

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Solution for 20(4c-3)+50c=590 equation: 



20(4c-3)+50c=590

We move all terms to the left:

20(4c-3)+50c-(590)=0

We add all the numbers together, and all the variables

50c+20(4c-3)-590=0

We multiply parentheses

50c+80c-60-590=0

We add all the numbers together, and all the variables

130c-650=0

We move all terms containing c to the left, all other terms to the right

130c=650

c=650/130

c=5

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