3p-2(4-2p)=4(p-4)-19

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Solution for 3p-2(4-2p)=4(p-4)-19 equation: 



3p-2(4-2p)=4(p-4)-19

We move all terms to the left:

3p-2(4-2p)-(4(p-4)-19)=0

We add all the numbers together, and all the variables

3p-2(-2p+4)-(4(p-4)-19)=0

We multiply parentheses

3p+4p-(4(p-4)-19)-8=0



We calculate terms in parentheses: -(4(p-4)-19), so:

4(p-4)-19

We multiply parentheses

4p-16-19

We add all the numbers together, and all the variables

4p-35

Back to the equation:

-(4p-35)



We add all the numbers together, and all the variables

7p-(4p-35)-8=0

We get rid of parentheses

7p-4p+35-8=0

We add all the numbers together, and all the variables

3p+27=0

We move all terms containing p to the left, all other terms to the right

3p=-27

p=-27/3

p=-9

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