1+3/5(q-4)=2/3(q+1)

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Solution for 1+3/5(q-4)=2/3(q+1) equation: 



1+3/5(q-4)=2/3(q+1)

We move all terms to the left:

1+3/5(q-4)-(2/3(q+1))=0



Domain of the equation: 5(q-4)!=0

q∈R





Domain of the equation: 3(q+1))!=0

q∈R



We calculate fractions


(9qq/(5(q-4)*3(q+1)))+(-10qq/(5(q-4)*3(q+1)))+1=0



We calculate terms in parentheses: +(9qq/(5(q-4)*3(q+1))), so:

9qq/(5(q-4)*3(q+1))

We multiply all the terms by the denominator


9qq

Back to the equation:

+(9qq)





We calculate terms in parentheses: +(-10qq/(5(q-4)*3(q+1))), so:

-10qq/(5(q-4)*3(q+1))

We multiply all the terms by the denominator


-10qq

Back to the equation:

+(-10qq)



We get rid of parentheses

9qq-10qq+1=0

We move all terms containing q to the left, all other terms to the right

9qq-10qq=-1

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