8(x+1)=-3(2+x)

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Solution for 8(x+1)=-3(2+x) equation: 



8(x+1)=-3(2+x)

We move all terms to the left:

8(x+1)-(-3(2+x))=0

We add all the numbers together, and all the variables

8(x+1)-(-3(x+2))=0

We multiply parentheses

8x-(-3(x+2))+8=0



We calculate terms in parentheses: -(-3(x+2)), so:

-3(x+2)

We multiply parentheses

-3x-6

Back to the equation:

-(-3x-6)



We get rid of parentheses

8x+3x+6+8=0

We add all the numbers together, and all the variables

11x+14=0

We move all terms containing x to the left, all other terms to the right

11x=-14

x=-14/11

x=-1+3/11

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