(3y+53)=(7y-5)

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Solution for (3y+53)=(7y-5) equation: 



(3y+53)=(7y-5)

We move all terms to the left:

(3y+53)-((7y-5))=0

We get rid of parentheses

3y-((7y-5))+53=0



We calculate terms in parentheses: -((7y-5)), so:

(7y-5)

We get rid of parentheses

7y-5

Back to the equation:

-(7y-5)



We get rid of parentheses

3y-7y+5+53=0

We add all the numbers together, and all the variables

-4y+58=0

We move all terms containing y to the left, all other terms to the right

-4y=-58

y=-58/-4

y=14+1/2

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