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1(x+2)-85=8(x-6)
We move all terms to the left:
1(x+2)-85-(8(x-6))=0
We calculate terms in parentheses: -(8(x-6)), so:We get rid of parentheses
8(x-6)
We multiply parentheses
8x-48
Back to the equation:
-(8x-48)
1(x+2)-8x+48-85=0
We add all the numbers together, and all the variables
-8x+1(x+2)-37=0
We move all terms containing x to the left, all other terms to the right
-8x+1(x+2)=37
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