(8-10x)(5x-4)=0

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Solution for (8-10x)(5x-4)=0 equation: 



(8-10x)(5x-4)=0

We add all the numbers together, and all the variables

(-10x+8)(5x-4)=0

We multiply parentheses ..

(-50x^2+40x+40x-32)=0

We get rid of parentheses

-50x^2+40x+40x-32=0

We add all the numbers together, and all the variables

-50x^2+80x-32=0

a = -50; b = 80; c = -32;
Δ = b2-4ac
Δ = 802-4·(-50)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-80}{-100}=4/5$

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