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4(x+2)-3=-2(x-5)
We move all terms to the left:
4(x+2)-3-(-2(x-5))=0
We multiply parentheses
4x-(-2(x-5))+8-3=0
We calculate terms in parentheses: -(-2(x-5)), so:We add all the numbers together, and all the variables
-2(x-5)
We multiply parentheses
-2x+10
Back to the equation:
-(-2x+10)
4x-(-2x+10)+5=0
We get rid of parentheses
4x+2x-10+5=0
We add all the numbers together, and all the variables
6x-5=0
We move all terms containing x to the left, all other terms to the right
6x=5
x=5/6
x=5/6
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