6+(3n-9)+45=12-4(9-2n)

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Solution for 6+(3n-9)+45=12-4(9-2n) equation: 



6+(3n-9)+45=12-4(9-2n)

We move all terms to the left:

6+(3n-9)+45-(12-4(9-2n))=0

We add all the numbers together, and all the variables

(3n-9)-(12-4(-2n+9))+6+45=0

We add all the numbers together, and all the variables

(3n-9)-(12-4(-2n+9))+51=0

We get rid of parentheses

3n-(12-4(-2n+9))-9+51=0



We calculate terms in parentheses: -(12-4(-2n+9)), so:

12-4(-2n+9)

determiningTheFunctionDomain
-4(-2n+9)+12

We multiply parentheses

8n-36+12

We add all the numbers together, and all the variables

8n-24

Back to the equation:

-(8n-24)



We add all the numbers together, and all the variables

3n-(8n-24)+42=0

We get rid of parentheses

3n-8n+24+42=0

We add all the numbers together, and all the variables

-5n+66=0

We move all terms containing n to the left, all other terms to the right

-5n=-66

n=-66/-5

n=13+1/5

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