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0=2x(x-21)
We move all terms to the left:
0-(2x(x-21))=0
We add all the numbers together, and all the variables
-(2x(x-21))=0
We calculate terms in parentheses: -(2x(x-21)), so:We get rid of parentheses
2x(x-21)
We multiply parentheses
2x^2-42x
Back to the equation:
-(2x^2-42x)
-2x^2+42x=0
a = -2; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-2)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-2}=\frac{-84}{-4} =+21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-2}=\frac{0}{-4} =0 $
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