(x+4)+(2x+11)=(4x-2)

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Solution for (x+4)+(2x+11)=(4x-2) equation: 



(x+4)+(2x+11)=(4x-2)

We move all terms to the left:

(x+4)+(2x+11)-((4x-2))=0

We get rid of parentheses

x+2x-((4x-2))+4+11=0



We calculate terms in parentheses: -((4x-2)), so:

(4x-2)

We get rid of parentheses

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

3x-(4x-2)+15=0

We get rid of parentheses

3x-4x+2+15=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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